multiply each equation by a number that producess opposite coefficients for x and y? 4x+5y=7 3x-2y=-12(number between =5 and 5 for both)

Let's solve your system by substitution. 3x−2y=−12;4x+5y=7 Step: Solve3x−2y=−12for x: 3x−2y=−12 3x−2y+2y=−12+2y(Add 2y to both sides) 3x=   2y−12 3          3= 2y−12 3 (Divide both sides by 3) x= 2 3    y−4 Step: Substitute 2 3 y−4 for x in 4x+5y=7: 4x+5y=7 4( 2/3  y−4)+5y=7 23 3 y−16=7(Simplify both sides of the equation) 23 3 y−16+16=7+16(Add 16 to both sides) 23 3 y=23 23 3  y 23 3      =  23 23 3 (Divide both sides by 23/3) y=3 Step: Substitute 3 for y in x=  2   3 y−4: x=  2   3 y−4 x=    2     3 (3)−4 x=−2(Simplify both sides of the equation) Answer: x=−2 and y=3                    (underlined and / are fractions or division)