MATH SOLVE

2 months ago

Q:
# What is the equation of the line passing through the points (2, β1) and (5, β10) in slope-intercept form?

Accepted Solution

A:

Answer:y = - 3x + 5Step-by-step explanation:The equation of a line in slope- intercept form isy = mx + c ( m is the slope and c the y- intercept )To calculate m use the slope formulam = ( yβ - yβ ) / ( xβ - xβ )with (xβ, yβ ) = (2, - 1) and (xβ, yβ ) = (5, - 10)m = [tex]\frac{-10+1}{5-2}[/tex] = [tex]\frac{-9}{3}[/tex] = - 3, hencey = - 3x + c β is the partial equationTo find c substitute either of the 2 points into the partial equationUsing (2, - 1 ), then- 1 = - 6 + c β c = - 1 + 6 = 5y = - 3x + 5 β equation in slope- intercept form