What is the equation of the line passing through the points (2, –1) and (5, –10) in slope-intercept form?
Accepted Solution
A:
Answer:y = - 3x + 5Step-by-step explanation:The equation of a line in slope- intercept form isy = mx + c ( m is the slope and c the y- intercept )To calculate m use the slope formulam = ( y₂ - y₁ ) / ( x₂ - x₁ )with (x₁, y₁ ) = (2, - 1) and (x₂, y₂ ) = (5, - 10)m = [tex]\frac{-10+1}{5-2}[/tex] = [tex]\frac{-9}{3}[/tex] = - 3, hencey = - 3x + c ← is the partial equationTo find c substitute either of the 2 points into the partial equationUsing (2, - 1 ), then- 1 = - 6 + c ⇒ c = - 1 + 6 = 5y = - 3x + 5 ← equation in slope- intercept form